2/u=3/u^2+1

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Solution for 2/u=3/u^2+1 equation: 


D( u )

u = 0

u^2 = 0

u = 0

u = 0

u^2 = 0

u^2 = 0

1*u^2 = 0 // : 1

u^2 = 0

u = 0

u in (-oo:0) U (0:+oo)

2/u = 3/(u^2)+1 // - 3/(u^2)+1

2/u-(3/(u^2))-1 = 0

2/u-3*u^-2-1 = 0

2*u^-1-3*u^-2-1 = 0

t_1 = u^-1

2*t_1^1-3*t_1^2-1 = 0

2*t_1-3*t_1^2-1 = 0

DELTA = 2^2-(-3*(-1)*4)

DELTA = -8

DELTA < 0

u belongs to the empty set

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